[tex] \boxed{ \bf \sqrt[x]{ \sqrt[y]{a} } = \sqrt[x]{ {a}^{ \frac{1}{x} } } ={ ({a }^{ \frac{1}{x} } )} ^{ \frac{1}{y} } = {a}^{ \frac{1}{xy} } }[/tex]
Buktikan Jika Sifat tersebut benar, dengan mengganti:
a → 64
y → 2
x → 3
[tex]\bf \sqrt[x]{ \sqrt[y]{a} } = \sqrt[x]{ {a}^{ \frac{1}{x} } } ={ ({a }^{ \frac{1}{x} } )} ^{ \frac{1}{y} } = {a}^{ \frac{1}{xy} } \\ \\ \sqrt[3]{ \sqrt[2]{64} } = {64}^{ \frac{1}{2 \times 3} } = {64}^{ \frac{1}{6} } \\ \\ = \sqrt[6]{64} = \sqrt[6]{ {2}^{6} } \\ \\ \boxed{ \bf = 2}[/tex]
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